User talk:Nyet: Difference between revisions

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<math>
<math>
e^{i\pi} + 1 = 0
\frac{4}{\sqrt{\pi}}
</math>
</math>

Revision as of 06:13, 25 September 2018

erfc(x)=2πxet2dt=ex2xπn=0(1)n(2n)!n!(2x)2n

DF(fi)=LF(D0+S0(c/fiλref))

eiπ+1=0