User talk:Nyet: Difference between revisions

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D_F(f_i) = L_F(D_0+S_0(c/f_i-\lambda_{ref}))
D_F(f_i) = L_F(D_0+S_0(c/f_i-\lambda_{ref}))
</math>
</math>

teast

Revision as of 17:34, 29 May 2018

erfc(x)=2πxet2dt=ex2xπn=0(1)n(2n)!n!(2x)2n

DF(fi)=LF(D0+S0(c/fiλref))