User talk:Nyet: Difference between revisions
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\frac{2}{\sqrt{\pi}} \int_x^{\infty} e^{-t^2}\,dt = |
\frac{2}{\sqrt{\pi}} \int_x^{\infty} e^{-t^2}\,dt = |
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\frac{e^{-x^2}}{x\sqrt{\pi}}\sum_{n=0}^\infty (-1)^n \frac{(2n)!}{n!(2x)^{2n}} |
\frac{e^{-x^2}}{x\sqrt{\pi}}\sum_{n=0}^\infty (-1)^n \frac{(2n)!}{n!(2x)^{2n}} |
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</math> |
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<math> |
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\frac{a}{b} |
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</math> |
</math> |
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Revision as of 00:51, 17 November 2016
